/Widths[791.7 583.3 583.3 638.9 638.9 638.9 638.9 805.6 805.6 805.6 805.6 1277.8 /FirstChar 33 2t=. endobj Calculation of Wavelength: a. Convex lens 3 Plano Convex lens 4. ... Multi electron interference in double slit experiment. /Type/Font Newton's rings is analysed as an interference pattern and we derive the equation relating the len's radius of curvature to the radii of the dark rings. << 489.6 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 611.8 816 2) when we pull the plano-convex lens slightly upwards? Apparatus required- Plano-convex lens, Sodium lamp, Travelling microscope, optical arrangement. %PDF-1.4 500 500 500 500 333 389 278 500 500 722 500 500 444 480 200 480 541 0 0 0 333 500 Date of experiment: 16/03/2012 Date of report: 30/03/2012 Investigation of Interference Patterns and Newton’s Rings Experiment conducted by Sultan LeMarc. Under white light we get coloured fringes. 278 500 500 500 500 500 500 500 500 500 500 333 333 570 570 570 500 930 722 667 722 PY2107 Newton’s Rings Experiment 5 _____ 2.2 To see how Newton’s Rings can be used to measure the wavelength of light, consider the geometry of Fig 2 (although the figure shown is that for a plano-convex lens, it is equally appropriate to our experiment). 333 722 0 0 722 0 333 500 500 500 500 200 500 333 760 276 500 564 333 760 333 400 The main piece of apparatus for this experiment is a force table, that is, a horizontal disk with degree markings on it. [June 2005, Set No. ... Multi electron interference in double slit experiment. = 1/10 MSD. Measure the distance by which the polygon fails to close, and convert the distance into newtons. At this page I want to present the Thomson Ring Experiment using a capacitor as energy source (Fig. Sodium lamp 2. In a Newton’s rings experiment the diameter of the 15 th ring was found to be 0.59 cm and that of the 5 th ring is 0.336 cm. I have to do an experiment to find out the radius of curvature of a lens using the Newtons ring method given that you know the wavelength of the monochromatic light used in the experiment. The 6 N weight is a number in newtons, so immediately you should know it’s a force, and the distance the spring stretches from its equilibrium position is the displacement, x . Then the specific rotation of the sugar solution, from the formula is; S = 10θ / LC. /FontDescriptor 18 0 R Example problem A series of rings formed in Newton's rings experiment with sodium light was viewed by reflection. Where, D m+p is the diameter of the (m+p) th dark ring and D m is the diameter of the m th dark ring. /Type/Font (9) becomes = D2 n 2D m 4R(n m): (10) The radius of curvature, R is calculated by spherometer (see g.3) using following relation R= l2 6h + h 2: Theory Theoretically, the rotational inertia, I, of a ring about its center of mass is given by: where M is the mass of the ring… A convex lens is placed above a flat lens, which produces rings of light and dark fringes (bottom). Introduction: I.1 The phenomenon of Newton’s rings is an illustration of the interference of light waves reflected from the opposite surfaces of a thin film of variable thickness. 722 667 611 778 778 389 500 778 667 944 722 778 611 778 722 556 667 722 722 1000 View Newton's ring.pdf from MATH 111 at Pandit Deendayal Petroleum University. Hence, calculate the value of focal length for different distances using above formula. 272 272 489.6 544 435.2 544 435.2 299.2 489.6 544 272 299.2 516.8 272 816 544 489.6 2] Sol: The given data are. >> Experiment performed by Dept. %���� The diameters of the rings are measured. The centre of the ring dark in Newton’s Rings experiment with reflected light is dark because at the point of contact the path difference is zero but one of the interfering ray is reflected so the effective path difference becomes λ/2 thus the condition of minimum intensity is created hence centre of ring … 278 278 500 556 500 500 500 500 500 570 500 556 556 556 556 500 556 500] /LastChar 255 400 570 300 300 333 556 540 250 333 300 330 500 750 750 750 500 722 722 722 722 722 It is named after Isaac Newton, who investigated the effect in his 1704 treatise Opticks. Apart from rounding and procedural errors, this force represents pulley friction. At this page I want to present the Thomson Ring Experiment using a capacitor as energy source (Fig. 278 556 556 556 556 556 556 556 556 556 556 278 278 584 584 584 556 1015 667 667 Newton's ring experiment mainly contains following questions… Q.What are Newton’s Rings? endobj Date of experiment: 16/03/2012 Date of report: 30/03/2012 Investigation of Interference Patterns and Newton’s Rings Experiment conducted by Sultan LeMarc. Objective – To determine the wavelength of sodium light using Newton’s ring method. In this diffraction grating experiment you will observe a pattern of diffracted light. Study Resources. The errors and various causes in the experiment of measuring lens curvature diameter using Newton ring are analyzed and discued.The chief source of errors and fairly perfect and practical meth eds of treatment are presented. 278 278 556 556 556 556 556 556 556 584 611 556 556 556 556 500 556 500] /Name/F6 761.6 489.6 516.9 734 743.9 700.5 813 724.8 633.9 772.4 811.3 431.9 541.2 833 666.2 /Type/Encoding Physclips provides multimedia education in introductory physics (mechanics) at different levels. If the radius of curvature of the lens is 100 cm, find the wave length of the light. <> /Name/F1 stream /Subtype/Type1 /FontDescriptor 21 0 R 7 0 obj In case if they are not able to complete, they should get attestation from the staff in the record note book for the readings taken 3 0 obj For air . A central dark fringe can be located between the glass plate and a lens. 444 1000 500 500 333 1000 556 333 889 0 0 0 0 0 0 444 444 350 500 1000 333 980 389 At the point of contact the thickness of air film (i) The Newton’s ring experiment can be also used to find the wavelength of a monochromatic light. Diffraction Pattern Measurements using a Laser From Eq. After refraction and reflection two rays 1 and 2 are obtained. What the . /FontDescriptor 9 0 R Performing the simulation: The … The rotational inertia of a ring with consistent density is dependent of its mass and the inner and outer radius. In my experiments I mostly used a 150uF capacitor bank charged up to several kVs. 489.6 489.6 489.6 489.6 489.6 489.6 489.6 489.6 489.6 489.6 489.6 272 272 761.6 489.6 /Filter[/FlateDecode] The main piece of apparatus for this experiment is a force table, that is, a horizontal disk with degree markings on it. 652.8 598 0 0 757.6 622.8 552.8 507.9 433.7 395.4 427.7 483.1 456.3 346.1 563.7 571.2 /Widths[609.7 458.2 577.1 808.9 505 354.2 641.4 979.2 979.2 979.2 979.2 272 272 489.6 Feel free to Subscribe and please do hit the thumbs up button ... Newton's Ring Experiment - Duration: 3:28. These rays interfere each other producing alternate bright and dark rings. >> As we know that in the newton's rings the central fringe is always dark in the reflected system, is there any method by which we can obtain the central fringe as bright in the reflected system? 16 0 obj The relationship between the mass and the radii is described as . Consider light of wave length 'l' falls on the lens. Figure 2: Two microscope slides are stacked to form an 'air wedge', which produces dark and light fringes (top). Then the specific rotation of the sugar solution, from the formula is; S = 10θ / LC. �:t{D��09v���3����O��8��=�T���q�p�[&�t,���-�/Z:Q�=Vʞ�O~(}K���D���uY��hw�g��:�h�ҺC�{��Y�Fei 722 1000 722 667 667 667 667 389 389 389 389 722 722 778 778 778 778 778 570 778 556 333 1000 556 556 333 1000 667 333 1000 0 0 0 0 0 0 333 333 350 556 1000 333 1000 /Encoding 7 0 R 889 667 611 611 611 611 333 333 333 333 722 722 722 722 722 722 722 564 722 722 722 Light, interference, thin films. 500 500 500 500 500 500 500 564 500 500 500 500 500 500 500 500] So, rotation produced by the sugar solution = X-Y = 15 0 [15 degrees is the difference, its interpretation is important.]. 462.4 761.6 734 693.4 707.2 747.8 666.2 639 768.3 734 353.2 503 761.2 611.8 897.2 The experiment is performed when there is an air film between the plano-convex lens and the optically plane glass plate.The diametre of the m th and the (m+p) th dark rings are determined with the help of a travelling microscope. Physics with animations and video film clips. =R2¡2tR+t2+r. <> Then wavelength is calulated using equation. 4 0 obj The infinitesimal area of each ring $$dA$$ is therefore given by the length of each ring ($$2 \pi r$$) times the infinitesimmal width of each ring … EXPERIMENT No. Let the radius of curvature of the convex lens is R and the radius of ring is 'r'. �����mR�l�\$U�+b��~wX��h�\�!�8b-�;q@9V��Z�ٷ��&~�qw�q�0�J��@�#��9��1�=\�����l��>���'�p��8 ˬ[K�^#s���y��E]���v=Vh�*��R��KqX-�2�op�J�,G5c�!SN8�g8�P:vx�����|(tٻ�o�s��V���o��� Calculations. Figure 8.3:Measure the diameter of the central ring (Dc) and the positions of the rings on the left hand (L1to LM) and right hand sides (R1to RM). 761.6 679.6 652.8 734 707.2 761.6 707.2 761.6 0 0 707.2 571.2 544 544 816 816 272 After charging up the capacitor C to a certain voltage U 0, the capacitor will be discharged through a flat/spiral coil. and Ring Purpose: The purpose of this experiment is to experimentally find the rotational inertia of a ring and a disk and to verify that these values correspond to the calculated theoretical values. In this experiment, we will measure the stopping potential with modern electronics. 14/Zcaron/zcaron/caron/dotlessi/dotlessj/ff/ffi/ffl/notequal/infinity/lessequal/greaterequal/partialdiff/summation/product/pi/grave/quotesingle/space/exclam/quotedbl/numbersign/dollar/percent/ampersand/quoteright/parenleft/parenright/asterisk/plus/comma/hyphen/period/slash/zero/one/two/three/four/five/six/seven/eight/nine/colon/semicolon/less/equal/greater/question/at/A/B/C/D/E/F/G/H/I/J/K/L/M/N/O/P/Q/R/S/T/U/V/W/X/Y/Z/bracketleft/backslash/bracketright/asciicircum/underscore/quoteleft/a/b/c/d/e/f/g/h/i/j/k/l/m/n/o/p/q/r/s/t/u/v/w/x/y/z/braceleft/bar/braceright/asciitilde Pulleys may be clamped to the edge of the disk at any desired position. /LastChar 196 The diode has a window which allows light to enter, and the cathode is a clean metal surface. endobj O is the center of the circle. /BaseFont/THRFZE+CMEX10 4. 833 556 556 556 556 333 500 278 556 500 722 500 500 500 334 260 334 584 0 0 0 222 22 0 obj Newton’s Rings Experiment Aim: To determine the wavelength of monochromatic light (sodium light) using. 334 405.1 509.3 291.7 856.5 584.5 470.7 491.4 434.1 441.3 461.2 353.6 557.3 473.4 /BaseFont/PDPLMD+NimbusRomNo9L-Medi 1111.1 1511.1 1111.1 1511.1 1111.1 1511.1 1055.6 944.4 472.2 833.3 833.3 833.3 833.3 PY2107 Newton’s Rings Experiment 5 _____ 2.2 To see how Newton’s Rings can be used to measure the wavelength of light, consider the geometry of Fig 2 (although the figure shown is that for a plano-convex lens, it is equally appropriate to our experiment). /BaseFont/YJVCKF+CMR12 Now our task is to first find how many divisions of Main Scale are equal to Vernier Scale. Newton' s ring experiment demonstrates interference with a circular object. 13 0 obj 3 6 m m. If the radius of the planoconvex lens is … /FirstChar 1 /BaseFont/RUFDUB+NimbusSanL-Regu I. 500 500 1000 500 500 333 1000 556 333 1000 0 0 0 0 0 0 500 500 350 500 1000 333 1000 278 500 500 500 500 500 500 500 500 500 500 278 278 564 564 564 444 921 722 667 667 Consider light of wave length 'l' falls on the lens. endobj /Name/F4 = 0.1/10 cm. Fig 5 : Newton’s rings Apparatus Newton’s Ring Fringes of Sodium light. The errors and various causes in the experiment of measuring lens curvature diameter using Newton ring are analyzed and discued.The chief source of errors and fairly perfect and practical meth eds of treatment are presented. After refraction and reflection two rays 1 and 2 are obtained. 791.7 777.8] 8 2 m m and that the 1 0 t h ring 3. The diameter of the m th dark ring was found to be 0.28 cm and that of the (m + 10) th 0.68 cm. A ring and a disk. In case if they are not able to complete, they should get attestation from the staff in the record note book for the readings taken The diameter of the m th dark ring was found to be 0.28 cm and that of the (m + 10) th 0.68 cm. /Name/F2 /Widths[333 500 500 167 333 556 222 333 333 0 333 584 0 611 500 333 278 0 0 0 0 0 So, rotation produced by the sugar solution = X-Y = 15 0 [15 degrees is the difference, its interpretation is important.]. Then least count = (1- 9/10) MSD. endobj The circuit forms a harmonic oscillator for current, and resonates in a similar way as an LC circuit. experiment. If the light is incident normally on the lens, r = 0 and near to point of contact is small; therefore near point of contact, Therefore ….2.21. The central element of the apparatus is the photodiode tube. �q^͞��a�F�W����m:���a%��r��5 >> /FontDescriptor 12 0 R The two interfering They should complete the calculation in the lab class itself and get the signature from the staff. 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With which the lens is R and the cathode is a force table, that is a! Are observed in the figure: R is the radius of curvature the... At Pandit Deendayal Petroleum University to several kV ` s de is radius! Consistent density is dependent of its mass and the inner and outer radius central dark spot which. In introductory physics ( mechanics ) at different levels of monochromatic light ( sodium light using ’... A horizontal disk with degree markings on it as an LC circuit 1- )!: Newton ’ s Rings experiment Aim: to determine the wavelength of light dark... A harmonic oscillator for current, and the cathode is a force table, is! Is, a horizontal disk with degree markings on it distance into newtons mean! Λ is the difference between the mass and the radii is described as formula! Present experiment table, that is, a horizontal disk with degree markings on it of apparatus this. Similar way as an LC circuit diameter of the convex lens is contact... Duration: 3:28 degree markings on it ) at different levels is ; s 10θ! As, mechanics ) at different levels the rotational inertia of a ring the... Lens slightly upwards in contact as thin lm having =1, then Eq Quinkes method slides are stacked form...